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x^2+1.25x-20000=0
a = 1; b = 1.25; c = -20000;
Δ = b2-4ac
Δ = 1.252-4·1·(-20000)
Δ = 80001.5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.25)-\sqrt{80001.5625}}{2*1}=\frac{-1.25-\sqrt{80001.5625}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.25)+\sqrt{80001.5625}}{2*1}=\frac{-1.25+\sqrt{80001.5625}}{2} $
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